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HIP6304 Datasheet(PDF) 10 Page - Intersil Corporation |
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HIP6304 Datasheet(HTML) 10 Page - Intersil Corporation |
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10 / 14 page  10 RIN should be selected to give the desired “droop” voltage at the normal full load current 50 µA applied through the RISEN resistor (or at a different full load current if adjusted as under “Over-Current, Selecting RISEN” above). RIN = Vdroop / 50µA For a Vdroop of 80mV, RIN = 1.6kΩ The AC feedback components, RFB and Cc, are scaled in relation to RIN. Current Balancing The detected currents are also used to balance the phase currents. Each phase’s current is compared to the average of the two phase currents, and the difference is used to create an offset in that phase’s PWM comparator. The offset is in a direction to reduce the imbalance. The balancing circuit can not make up for a difference in rDS(ON) between synchronous rectifiers. If a FET has a higher rDS(ON), the current through that phase will be reduced. Figures 8 and 9 show the inductor current of a two phase system without and with current balancing. Inductor Current The inductor current in each phase of a multi-phase Buck converter has two components. There is a current equal to the load current divided by the number of phases (ILT / n), and a sawtooth current, (iPK-PK) resulting from switching. The sawtooth component is dependent on the size of the inductors, the switching frequency of each phase, and the values of the input and output voltage. Ignoring secondary effects, such as series resistance, the peak to peak value of the sawtooth current can be described by: iPK-PK = (VIN x VCORE - VCORE 2) / (L x F SW x VIN) Where: VCORE = DC value of the output or VID voltage VIN = DC value of the input or supply voltage L = value of the inductor FSW = switching frequency Example: For VCORE = 1.6V, VIN = 12V, L = 1.3 µH, FSW = 250kHz, Then iPK-PK = 4.3A The inductor, or load current, flows alternately from VIN through Q1 and from ground through Q2. The HIP6304 samples the on-state voltage drop across each Q2 transistor to indicate the inductor current in that phase. The voltage drop is sampled 1/3 of a switching period, 1/FSW, after Q1 is turned OFF and Q2 is turned on. Because of the sawtooth current component, the sampled current is different from the average current per phase. Neglecting secondary effects, the sampled current (ISAMPLE) can be related to the load current (ILT) by: ISAMPLE = ILT /n+ (VINVCORE -3VCORE 2) / (6L x F SW xVIN) Where: ILT = total load current n = the number of channels 0 5 10 15 20 25 FIGURE 8. TWO CHANNEL MULTIPHASE SYSTEM WITH CURRENT BALANCING DISABLED 0 5 10 15 20 25 FIGURE 9. TWO CHANNEL MULTIPHASE SYSTEM WITH CURRENT BALANCING ENABLED HIP6304 HIP6304 |
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