SP6203EM5-L datasheet(10/15 Pages) EXAR

Part #	SP6203EM5-L

Description	300mA/500mA Low Noise CMOS LDO Regulators

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Manufacturer	EXAR [Exar Corporation]

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time (TWU) and the settling time (TS). The

wake up time is defined as the time it takes

for the output to rise to 2% of its total value

after being released from shutdown (EN >

0.4V). The settling time is defined as the

condition where the output reaches 98% of its

total

value

after

being

released

from

shutdown. The latter is also called the turn on

time and is dependent on the output capacitor,

a little bit on load and, if present, on a bypass

capacitor.

TURN OFF TIME

The turn off time is defined as the condition

where the output voltage drops about 66% (θ)

of its total value. 5θ to 7θ is the constant

where the output voltage drops nearly to zero.

There will always be a small voltage drop in

shutdown because of the switch unless we

short-circuit it. The turn off time of the output

voltage is dependent on load conditions,

output capacitance on VOUT (time constant  =

RLCL) and also on the difference in voltage

between input and output.

THERMAL CONSIDERATIONS

The SP6203/6205 is designed to provide

300/500mA of continuous current in a tiny

package. Maximum power dissipation can be

calculated based on the output current and the

voltage drop across the part. To determine the

maximum power dissipation of the package,

use

the

junction-to-ambient

thermal

resistance of the device and the following

basic equation:

PD = (TJ(max) - TA) / θJA

TJ(max) is the maximum junction temperature of

the die and is 125°C. TA is the ambient

temperature. θJA is the junction-to-ambient

thermal resistance for the regulator and is

layout dependent. The SOT-23-5 package has

a θJA of approximately 191°C/W for minimum

PCB copper footprint area.

This results in a maximum power dissipation

of:

PD(max)=[(125°C-25°C)/(191°C/W)] = 523mW

The actual power dissipation of the regulator

circuit can be determined using one simple

equation:

PD = (VIN - VOUT) * IOUT + VIN * IGND

To prevent the device from entering thermal

shutdown, maximum power dissipation cannot

be exceeded.

Substituting PD(max) for PD and solving for the

operating conditions that are critical to the

application will give the maximum operating

conditions for the

regulator circuit. For

example, if we are operating the SP6203 3.0V

at

room temperature, with

a minimum

footprint layout and output current of 300mA,

the

maximum

input

voltage

can

be

determined, based on the equation below.

Ground pin current can be taken from the

electrical specifications table (0.23mA at

300mA).

390mW = (VIN-3.0V) * 300mA + VIN *0.23mA

After calculations, we find that the maximum

input voltage of a 3.0V application at 300mA

of output current in a SOT-23-5 package is

4.7V.

So if the intent is to operate a 5V output

version from a 6V supply at 300mA load and

at a 25°C ambient temperature, then the

actual total power dissipation will be:

PD=([6V-5V]*[300mA])+(6V*0.23mA)=301.4mW

This is well below the 523mW package maxi-

mum. Therefore, the regulator can be used.

Note that the regulator cannot always be used

at its maximum current rating. For example, in

a 5V input to 3.0V output application at an

ambient temperature of 25°C and operating at

the full 500mA (IGND=0.355mA) load, the

regulator is limited to a much lower load

current, determined by the following equation:

523mW = ( [5V-3V]*[ Iload(max)]) +(5V*0.350mA)

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