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## APW7158 Datasheet(PDF) 17 Page - Anpec Electronics Coropration

 Part # APW7158 Description Dual Synchronous Buck PWM Controllers Download 24 Pages Scroll/Zoom 100% Manufacturer ANPEC [Anpec Electronics Coropration] Direct Link http://www.anpec.com.tw Logo

## APW7158 Datasheet(HTML) 17 Page - Anpec Electronics Coropration

 17 / 24 pageCopyright© ANPEC Electronics Corp.Rev. A.2 - Aug., 2009APW7158www.anpec.com.tw17Application Information (Cont.)PWM Compensation (Cont.)VCOMPC2VOUTR3VREFC1VFB-+C3R2R1Figure 8. Compensation NetworkThe closed loop gain of the converter can be written as:AMPPWMLCGAINGAINGAIN××Figure 9. Shows the asymptotic plot of the closed loopconverter gain and the following guidelines will help todesign the compensation network. Using the belowguidelines should give a compensation similar to thecurve plotted. A stable closed loop has a -20dB/ decadeslope and a phase margin greater than 45 degree.1. Choose a value for R1, usually between 1K and 5K.2. Select the desired zero crossover frequency FO:(1/5 ~ 1/10) x FS >FO>FESRUse the following equation to calculate R2:1RFFVV2RLCOINOSC××∆=3. Place the first zero FZ1 before the output LC filterdouble pole frequency FLC.FZ1 = 0.75 x FLCCalculate the C2 by the equation:75.0F2R212CLC ×××π×=4.Set the pole at the ESR zero frequency FESR:FP1 = FESRCalculate the C1 by the equation:1F2C2R22C1CESR −×××π×=5. Set the second pole FP2 at half the switching frequencyand also set the second zero FZ2 at the output LC filterdouble pole FLC. The compensation gain should not ex-ceed the error amplifier open loop gain, check the com-pensation gain at FP2 with the capabilities of the erroramplifier.FP2 = 0.5xFOFZ2 = FLCCombine the two equations will get the following compo-nent calculations:1F2F1R3RLCS−×=SF3R13C××π=Gain0FLCFESRFP2=0.5FSFZ1=0.75FLCFOFrequencyPWM & FilterGainCompensationGainConverterGainFZ2=FLCFP1=FESR20log(VIN/ VOSC)20log(R2/R1)Open Loop ErrorAmp GainFigure 9. Converter Gain & FrequencyOutput Inductor SelectionThe inductor value determines the inductor ripple currentand affects the load transient response. Higher inductorvalue reduces the inductor’s ripple current and induceslower output ripple voltage. The ripple current and ripplevoltage can be approximated by:INOUTSOUTINRIPPLEVVLFVVI××−=ESRIVOUTRIPPLE ×=∆

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