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F1206A0R25FWTR Datasheet(PDF) 10 Page - AVX Corporation |
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F1206A0R25FWTR Datasheet(HTML) 10 Page - AVX Corporation |
10 / 12 page 32 Fig. 2c. Choice of 0.75A fuse, example #2. Pre-arcing I2t Maximum I2t design rule I2t for sample switch-on pulse Accu-Guard® SMD Thin-Film Fuse t l max. Fig. 1a. Sine wave pulse parameters for Joule integral calculation, example #1. Thus, for the current pulse in Figure 1b, the Joule integral is [(4.8A)2 x 7.7 x 10-6 sec]/2 = 8.9 x 10-5 A2 sec. The pulse duration is 7.7μsec. We must find a fuse that can absorb at least 8.9 x 10-5 X 2 = 1.8 x 10-4 A2sec Joule inte- gral within 7.7 μsec without actuation. According to the I2t graph on page 6, pre-arcing Joule integral is 2.3x10-4 A2sec for the 0.5A fuse, which is slightly more than needed. The next lower rating (0.375A), has only 6x10-5 A2sec, which is not enough. Therefore, 0.5A fuse should be chosen for this application, see Figure 1c. FUSE PRE-ARCING JOULE INTEGRALS vs. PRE-ARCING TIME 2. Triangular current pulse The Joule integral for triangular pulse is [(Imax.)2 x t]/3, see Fig. 2a. Fig. 2a. Triangular pulse parameters for Joule integral calculation, example #2. t l max. Thus, for the current pulse in Figure 2b, the Joule integral is [(1.5A)2 x 3 x 10-3 sec]/3 = 2.25 x 10-3 A2sec. Fig. 1b. Sine wave pulse, example #1. Fig. 2b. Triangular pulse, example #2. The pulse duration is 3 msec. In the I2t graph on page 6, pre- arcing Joule integral for 3 msec pulse is 4 x 10-3A2sec for the 0.5A fuse (not enough) and 2 x 10-2 for the 0.75A fuse (more than enough). Therefore, 0.75A fuse should be chosen for this application, see Figure 2c. FUSE PRE-ARCING JOULE INTEGRALS vs. PRE-ARCING TIME 0.75A PRE-ARCING TIME l2t, A2 sec PRE-ARCING TIME, sec 100 10 1 10-1 10-2 10-3 10-4 10-5 10-7 10-6 10-5 10-4 10-3 10-2 10-1 110 x X 10 μsec/div 1A/div 2 msec/div 0.5A/div 0.5A PRE-ARCING TIME l2t, A2 sec PRE-ARCING TIME, sec 100 10 1 10-1 10-2 10-3 10-4 10-5 10-7 10-6 10-5 10-4 10-3 10-2 10-1 110 x X Fig. 1c. Choice of 0.5A fuse, example #1. Pre-arcing I2t Maximum I2t design rule I2t for sample current pulse DESIGNING FOR CURRENT PULSE SITUATIONS 1. Sine wave current pulse The Joule integral for sine wave pulse is [(I max.) 2 x t]/2, see Fig. 1a. |
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