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LTC6101AIMS8 Datasheet(PDF) 8 Page - Linear Technology |
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LTC6101AIMS8 Datasheet(HTML) 8 Page - Linear Technology |
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8 / 20 page  LTC6101/LTC6101HV 8 6101fa OUT (Pin 1): Current Output. OUT (Pin 1) will source a current that is proportional to the sense voltage into an external resistor. V– (Pin 2): Negative Supply (or Ground for Single-Supply Operation). IN– (Pin 3): The internal sense amplifier will drive IN– (Pin 3) to the same potential as IN+ (Pin 4). A resistor (RIN) tied from V+ to IN– sets the output current IOUT = VSENSE/RIN. VSENSE is the voltage developed across the external RSENSE (Figure 1). IN+ (Pin 4): Must be tied to the system load end of the sense resistor, either directly or through a resistor. V+ (Pin 5): Positive Supply Pin. Supply current is drawn through this pin. The circuit may be configured so that the LTC6101 supply current is or is not monitored along with the system load current. To monitor only system load current, connect V+ to the more positive side of the sense resistor. To monitor the total current, including the LTC6101 current, connect V+ to the more negative side of the sense resistor. Figure 1. LTC6101/LTC6101HV Block Diagram and Typical Connection The LTC6101 high side current sense amplifier (Figure 1) provides accurate monitoring of current through a user- selected sense resistor. The sense voltage is amplified by a user-selected gain and level shifted from the positive power supply to a ground-referred output. The output signal is analog and may be used as is or processed with an output filter. Theory of Operation An internal sense amplifier loop forces IN– to have the same potential as IN+. Connecting an external resistor, RIN, between IN– and V+ forces a potential across RIN that is the same as the sense voltage across RSENSE. A corre- sponding current, VSENSE/RIN, will flow through RIN. The high impedance inputs of the sense amplifier will not conduct this input current, so it will flow through an internal MOSFET to the output pin. The output current can be transformed into a voltage by adding a resistor from OUT to V–. The output voltage is then VO = V– + IOUT • ROUT. 4 3 5 2 1 IN– V+ V– 10V OUT 6101 BD IN+ LTC6101/LTC6101HV VBATTERY IOUT VSENSE RSENSE ILOAD ROUT RIN – + L O A D VOUT = VSENSE x ROUT RIN 5k 5k 10V PI FU CTIO S BLOCK DIAGRA APPLICATIO S I FOR ATIO |
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