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V048T240M012A Datasheet(PDF) 11 Page - Vicor Corporation |
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V048T240M012A Datasheet(HTML) 11 Page - Vicor Corporation |
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11 / 18 page  Not Recommended for New Designs VTM™ Current Multiplier Rev 1.2 vicorpower.com Page 11 of 18 09/2015 800 927.9474 V048x240y012A 11.0 SINE AMPLITUDE CONVERTERTM POINT OF LOAD CONVERSION The Sine Amplitude Converter (SAC) uses a high frequency resonant tank to move energy from input to output. (The resonant tank is formed by Cr and leakage inductance Lr in the power transformer windings as shown in the VTM module Block Diagram. See Section 10). The resonant LC tank, operated at high frequency, is amplitude modulated as a function of input voltage and output current. A small amount of capacitance embedded in the input and output stages of the module is sufficient for full functionality and is key to achieving power density. The V048x240y012A SAC can be simplified into the following model: At no load: VOUT = VIN • K (1) K represents the “turns ratio” of the SAC. Rearranging Eq (1): K= VOUT (2) VIN In the presence of load, VOUT is represented by: VOUT = VIN • K – IOUT • ROUT (3) and IOUT is represented by: IOUT = IIN –IQ (4) K ROUT represents the impedance of the SAC, and is a function of the RDSON of the input and output MOSFETs and the winding resistance of the power transformer. IQ represents the quiescent current of the SAC control and gate drive circuitry. The use of DC voltage transformation provides additional interesting attributes. Assuming that ROUT = 0 Ω and IQ = 0 A, Eq. (3) now becomes Eq. (1) and is essentially load independent, resistor R is now placed in series with VIN as shown in Figure 15. The relationship between VIN and VOUT becomes: VOUT = (VIN –IIN • R) • K (5) Substituting the simplified version of Eq. (4) (IQ is assumed = 0 A) into Eq. (5) yields: VOUT = VIN • K – IOUT • R • K2 (6) + – + – VOUT COUT VIN V•I K + – + – CIN IOUT RCOUT IQ ROUT RCIN 123 mA 1/2 • IOUT 1/2 • VIN 43.4 m Ω RCIN 2.2 m Ω 2000 pH 0.006 Ω RCOUT 417 µ Ω 12 µF LOUT = 600 pH 2 µF IQ LIN = 0.6 nH IOUT ROUT VIN VOUT R SAC K = 1/32 Vin Vout + – VIN VOUT R SAC™ K = 1/32 Figure 15 — K = 1/32 Sine Amplitude Converter™ with series input resistor Figure 14 — VI Chip® module AC model COUT CIN |
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