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LM25018 Datasheet(PDF) 9 Page - Texas Instruments

Part # LM25018
Description  LM25018 48-V, 325-mA Constant On-Time Synchronous Buck Regulator
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Manufacturer  TI [Texas Instruments]
Direct Link  http://www.ti.com
Logo TI - Texas Instruments

LM25018 Datasheet(HTML) 9 Page - Texas Instruments

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FB
SW
L1
COUT
RFB2
VOUT
RC
LM25018
+
RFB1
VOUT
(low ripple)
RFB2 + RFB1
VOUT = 1.225V x
RFB1
OUT
SW
11
ON
V
f
9
10
R
-
=
´
´
LM25018
www.ti.com
SNVS953D – DECEMBER 2012 – REVISED DECEMBER 2014
7.3 Feature Description
7.3.1 Control Overview
The LM25018 buck regulator employs a control principle based on a comparator and a one-shot on-timer, with
the output voltage feedback (FB) compared to an internal reference (1.225 V). If the FB voltage is below the
reference the internal buck switch is turned on for the one-shot timer period, which is a function of the input
voltage and the programming resistor (RON). Following the on-time the switch remains off until the FB voltage
falls below the reference, but never before the minimum off-time forced by the minimum off-time one-shot timer.
When the FB pin voltage falls below the reference and the minimum off-time one-shot period expires, the buck
switch is turned on for another on-time one-shot period. This will continue until regulation is achieved and the FB
voltage is approximately equal to 1.225 V (typ).
In a synchronous buck converter, the low side (sync) FET is on when the high side (buck) FET is off. The
inductor current ramps up when the high side switch is on and ramps down when the high side switch is off.
There is no diode emulation feature in this IC, and therefore, the inductor current may ramp in the negative
direction at light load. This causes the converter to operate in continuous conduction mode (CCM) regardless of
the output loading. The operating frequency remains relatively constant with load and line variations. The
operating frequency can be calculated as shown in Equation 1.
(1)
The output voltage (VOUT) is set by two external resistors (RFB1, RFB2). The regulated output voltage is calculated
as shown in Equation 2.
(2)
This regulator regulates the output voltage based on ripple voltage at the feedback input, requiring a minimum
amount of ESR for the output capacitor (COUT). A minimum of 25 mV of ripple voltage at the feedback pin (FB) is
required for the LM25018. In cases where the capacitor ESR is too small, additional series resistance may be
required (RC in Figure 10).
For applications where lower output voltage ripple is required the output can be taken directly from a low ESR
output capacitor, as shown in Figure 10. However, RC slightly degrades the load regulation.
Figure 10. Low Ripple Output Configuration
7.3.2 VCC Regulator
The LM25018 device contains an internal high voltage linear regulator with a nominal output of 7.6 V. The input
pin (VIN) can be connected directly to the line voltages up to 48 V. The VCC regulator is internally current limited
to 30 mA. The regulator sources current into the external capacitor at VCC. This regulator supplies current to
internal circuit blocks including the synchronous MOSFET driver and the logic circuits. When the voltage on the
VCC pin reaches the undervoltage lockout threshold of 4.5 V, the IC is enabled.
The VCC regulator contains an internal diode connection to the BST pin to replenish the charge in the gate drive
boot capacitor when SW pin is low.
At high input voltages, the power dissipated in the high voltage regulator is significant and can limit the overall
achievable output power. As an example, with the input at 48 V and switching at high frequency, the VCC
regulator may supply up to 7 mA of current resulting in 48 V × 7 mA = 336 mW of power dissipation. If the VCC
voltage is driven externally by an alternate voltage source, between 8.55 V and 14 V, the internal regulator is
disabled. This reduces the power dissipation in the IC.
Copyright © 2012–2014, Texas Instruments Incorporated
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