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2N5191G Datasheet(PDF) 5 Page - ON Semiconductor |
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2N5191G Datasheet(HTML) 5 Page - ON Semiconductor |
5 / 6 page 2N5190G, 2N5191G, 2N5192G http://onsemi.com 5 10 1.0 Figure 11. Rating and Thermal Data Active−Region Safe Operating Area VCE, COLLECTOR-EMITTER VOLTAGE (VOLTS) 5.0 2.0 1.0 0.5 0.1 2.0 5.0 10 20 50 100 SECONDARY BREAKDOWN LIMIT THERMAL LIMIT AT TC = 25°C BONDING WIRE LIMIT 0.2 CURVES APPLY BELOW RATED VCEO TJ = 150°C dc 1.0ms 100 ms 2N5191 2N5192 5.0ms There are two limitations on the power handling ability of a transistor; average junction temperature and second breakdown. Safe operating area curves indicate IC − VCE limits of the transistor that must be observed for reliable operation; i.e., the transistor must not be subjected to greater dissipation than the curves indicate. The data of Figure 11 is based on TJ(pk) = 150 _C; TC is variable depending on conditions. Second breakdown pulse limits are valid for duty cycles to 10% provided TJ(pk) ≤ 150_C. At high case temperatures, thermal limitations will reduce the power that can be handled to values less than the limitations imposed by second breakdown. Figure 12. Thermal Response t, TIME OR PULSE WIDTH (ms) 1.0 0.01 0.01 0.7 0.5 0.3 0.2 0.1 0.07 0.05 0.03 0.02 0.02 0.03 0.05 0.1 0.2 0.3 0.5 1.0 2.0 3.0 5.0 10 20 50 100 200 1000 500 qJC(max) = 3.12°C/W — 2N5190-92 D = 0.5 0.2 0.05 0.02 0.01 SINGLE PULSE 0.1 DESIGN NOTE: USE OF TRANSIENT THERMAL RESISTANCE DATA tP PP PP t1 1/f DUTY CYCLE, D = t1 f - t1 tP PEAK PULSE POWER = PP Figure A A train of periodical power pulses can be represented by the model shown in Figure A. Using the model and the device thermal response, the normalized effective transient thermal resistance of Figure 12 was calculated for various duty cycles. To find qJC(t), multiply the value obtained from Figure 12 by the steady state value qJC. Example: The 2N5190 is dissipating 50 watts under the following conditions: t1 = 0.1 ms, tp = 0.5 ms. (D = 0.2). Using Figure 12, at a pulse width of 0.1 ms and D = 0.2, the reading of r(t1, D) is 0.27. The peak rise in function temperature is therefore: DT = r(t) × PP × qJC = 0.27 × 50 × 3.12 = 42.2_C |
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