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TC2015-2.6VCTTR Datasheet(PDF) 11 Page - Microchip Technology |
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TC2015-2.6VCTTR Datasheet(HTML) 11 Page - Microchip Technology |
11 / 20 page 2001-2012 Microchip Technology Inc. DS21662F-page 11 TC2014/2015/2185 5.0 THERMAL CONSIDERATIONS 5.1 Thermal Shutdown Integrated thermal protection circuitry shuts the regula- tor off when the die temperature exceeds approxi- mately 160°C. The regulator remains off until the die temperature cools to approximatley 150°C. 5.2 Power Dissipation The amount of power the regulator dissipates is primar- ily a function of input voltage, output voltage and output current. The following equation is used to calculate worst-case power dissipation. EQUATION 5-1: The maximum allowable power dissipation (PDMAX) is a function of the maximum ambient temperature (TAMAX), the maximum allowable die temperature (TJMAX) (+125°C) and the thermal resistance from junc- tion-to-air ( JA). The 5-Pin SOT-23A package has a JA of approximately 220°C/Watt when mounted on a typical two-layer FR4 dielectric copper-clad PC board. EQUATION 5-2: The PD equation can be used in conjunction with the PDMAX equation to ensure that regulator thermal operation is within limits. For example: Actual power dissipation: Maximum allowable power dissipation: In this example, the TC2014 dissipates a maximum of only 26.7 mW; far below the allowable limit of 318 mW. In a similar manner, the PD and PDMAX equations can be used to calculate maximum current and/or input voltage limits. 5.3 Layout Considerations The primary path of heat conduction out of the package is via the package leads. Therefore, layouts having a ground plane, wide traces at the pads and wide power supply bus lines combine to lower JA and, therefore, increase the maximum allowable power dissipation limit. P D V INMAX V OUTMIN – I LMAX Where: PD = Worst-case actual power dissipation VINMAX = Maximum voltage on VIN VOUTMIN = Minimum regulator output voltage ILMAX = Maximum output (load) current Where all terms are previously defined. P DMA X T JMAX T AMAX – JA --------------------------------------- = Given: VINMAX = 3.0V +10% VOUTMIN = 2.7V – 2.5% ILOADMAX =40 mA TJMAX = +125°C TAMAX = +55°C Find: 1. Actual power dissipation 2. Maximum allowable dissipation P D V INMA X V OUTMIN – I LMAX = 3.0 1.1 2.7 0.975 – 40 10 3 – = 26.7mW = P DMAX T JMAX T AMAX – JA --------------------------------------- = 125 55 – 220 --------------------- = 318mW = |
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