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TPS75201QPWPG4 Datasheet(PDF) 21 Page - Texas Instruments |
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TPS75201QPWPG4 Datasheet(HTML) 21 Page - Texas Instruments |
21 / 31 page www.ti.com Board thickness 62 mils(0.15748cm) Boardsize 3.2in.x3.2in. Boardmaterial FR4 Coppertrace/heatsink 1 oz Exposedpadmounting 63/67tin/lead(Sn/Pb)solder Heatsink Area 1ozCopper P = D(Max) T T R - J(Max) A JA (System) q (5) P =(V V ) I +V I - D(total) IN OUT OUT IN Q ´ ´ (6) P =(V V ) I - D(total) IN OUT OUT ´ (7) P = D(Max) T T R - J(Max) A JA (System) q = =1.4W 125 - ° C ° ° C C/W 55 50 (8) P =(V V ) I - D(total) IN OUT OUT ´ =(5 3.3) 0.8=1.36W - ´ (9) TPS752xxQ TPS754xxQ SLVS242C – MARCH 2000 – REVISED OCTOBER 2007 Figure 29 is an example of a thermally-enhanced PWB layout for use with the new PWP package. This board configuration was used in the thermal experiments that generated the power ratings shown in Figure 27 and Figure 28. As discussed earlier, copper has been added on the PWB to conduct heat away from the device. RθJA for this assembly is illustrated in Figure 27 as a function of heatsink area. A family of curves is included to illustrate the effect of airflow introduced into the system. Figure 29. PWB Layout (Including Copper Heatsink Area) for Thermally-Enhanced PWP Package From Figure 27, RθJA for a PWB assembly can be determined and used to calculate the maximum power-dissipation limit for the component/PWB assembly, with the equation: Where TJmax is the maximum specified junction temperature (+150°C absolute maximum limit, +125°C recommended operating limit) and TA is the ambient temperature. PD(max) should then be applied to the internal power dissipated by the TPS75433QPWP regulator. The equation for calculating total internal power dissipation of the TPS75433QPWP is: Because the quiescent current of the TPS75433QPWP is very low, the second term is negligible, further simplifying the equation to: For the case where TA = +55°C, airflow = 200 ft/min, copper heat-sink area = 4 cm 2, the maximum power-dissipation limit can be calculated. First, from Figure 27, we find the system RθJA is 50°C/W; therefore, the maximum power-dissipation limit is: If the system implements a TPS75433QPWP regulator, where VIN = 5 V and IOUT = 800 mA, the internal power dissipation is: Comparing PD(total) with PD(max) reveals that the power dissipation in this example does not exceed the calculated limit. When it does, one of two corrective actions should be made: either raise the power-dissipation limit by increasing the airflow or the heat-sink area, or loweri the internal power dissipation of the regulator by reducing the input voltage or the load current. In either case, the above calculations should be repeated with the new system parameters. Copyright © 2000–2007, Texas Instruments Incorporated Submit Documentation Feedback 21 |
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