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XN4604 Datasheet(PDF) 2 Page - Panasonic Semiconductor |
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XN4604 Datasheet(HTML) 2 Page - Panasonic Semiconductor |
2 / 5 page XN04604 2 SJJ00084BED • Tr2 ■ Electrical Characteristics T a = 25°C ± 3°C • Tr1 Parameter Symbol Conditions Min Typ Max Unit Collector-base voltage (Emitter open) VCBO IC = −10 µA, IE = 0 −15 V Collector-emitter voltage (Base open) VCEO IC = −1 mA, IB = 0 −10 V Emitter-base voltage (Collector open) VEBO IE = −10 µA, I C = 0 −7V Collector-base cutoff current (Emitter open) ICBO VCB = −10 V, IE = 0 − 0.1 µA Forward current transfer ratio * hFE1 VCE = −2 V, IC = − 0.5 A 100 350 hFE2 VCE = −2 V, I C = −1 A 60 Collector-emitter saturation voltage VCE(sat) IC = − 0.4 A, IB = −8 mA − 0.16 − 0.30 V Base-emitter saturation voltage VBE(sat) IC = − 0.4 A, IB = −8 mA − 0.8 −1.2 V Transition frequency fT VCB = −10 V, I E = 50 mA, f = 200 MHz 130 MHz Collector output capacitance Cob VCB = −10 V, I E = 0, f = 1 MHz 22 pF (Common base, input open circuited) Note) 1. Measuring methods are based on JAPANESE INDUSTRIAL STANDARD JIS C 7030 measuring methods for transistors. 2. *: Pulse measurement Note) 1. Measuring methods are based on JAPANESE INDUSTRIAL STANDARD JIS C 7030 measuring methods for transistors. 2. *1: Pulse measurement *2: Ron test circuit Parameter Symbol Conditions Min Typ Max Unit Collector-base voltage (Emitter open) VCBO IC = 10 µA, IE = 025 V Collector-emitter voltage (Base open) VCEO IC = 1 mA, I B = 020 V Emitter-base voltage (Collector open) VEBO IE = 10 µA, IC = 012 V Collector-base cutoff current (Emitter open) ICBO VCB = 25 V, IE = 0 0.1 µA Forward current transfer ratio * 1 hFE1 VCE = 2 V, I C = 0.5 A 200 800 hFE2 VCE = 2 V, IC = 1 A 60 Collector-emitter saturation voltage * 1 VCE(sat) IC = 0.5 A, IB = 20 mA 0.13 0.40 V Base-emitter saturation voltage * 1 VBE(sat) IC = 0.5 A, I B = 20 mA 1.2 V Transition frequency fT VCB = 10 V, IE = −50 mA, f = 200 MHz 200 MHz Collector output capacitance Cob VCB = 10 V, IE = 0, f = 1 MHz 10 pF (Common base, input open circuited) ON resistance * 2 Ron 1.0 Ω VV 1 k Ω Ron = VB × 1 000 ( Ω) VA − VB f = 1 kHz V = 0.3 V VB IB = 1 mA V A |
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